Logic Puzzle #1: The Missing Link

A great skill to master is the capability to conceptualize a fragment or structure directly off a spectrum without resorting to paper-and-pen work. This skill is learnt through lots of practice. Whenever partial information is available, an elucidator can conjure up a mental image of possibilities and should it be required instinctively hunt for any missing data.

In the following example, a set of fragments including 13C and 1H chemical shifts and long-range coupling information were extracted from an HMBC experiment (not shown). The green arrows represent the 2-3J coupling responses between the 3 equivalent methyl groups and the carbonyl’s quaternary carbon. Based on these restrictions, what fragment(s) support the data and is there anything missing?

To accommodate these restrictions, three potential fragments, assigned A, B and C, are shown below. Fragment A can be disregarded on the basis of the carbon valence. Fragment B is not a good candidate because the CH3 chemical shifts do not support the presence of an adjacent heteroatom. Fragment C seems to be the most logical choice. However, there is a missing quaternary carbon. The next step is to re-evaluate the NMR data in search of a weak 13C signal at ~40 ppm.

Logic Puzzle #1: The Missing Link

A great skill to master is the capability to conceptualize a fragment or structure directly off a spectrum without resorting to paper-and-pen work. This skill is learnt through lots of practice. Whenever partial information is available, an elucidator can conjure up a mental image of possibilities and should it be required instinctively hunt for any missing data.

In the following example, a set of fragments including 13C and 1H chemical shifts and long-range coupling information were extracted from an HMBC experiment (not shown). The green arrows represent the 2-3J coupling responses between the 3 equivalent methyl groups and the carbonyl’s quaternary carbon. Based on these restrictions, what fragment(s) support the data and is there anything missing?

To accommodate these restrictions, three potential fragments, assigned A, B and C, are shown below. Fragment A can be disregarded on the basis of the carbon valence. Fragment B is not a good candidate because the CH3 chemical shifts do not support the presence of an adjacent heteroatom. Fragment C seems to be the most logical choice. However, there is a missing quaternary carbon. The next step is to re-evaluate the NMR data in search of a weak 13C signal at ~40 ppm.

Signals can simply disappear on a DEPT-135 experiment

There are many advantages in working with a 1H-13C HSQC-DEPT spectrum over a 13C DEPT-135 and a 1H-13C HSQC (see Post 1 & Post 2). In most cases, a 1H-13C HSQC-DEPT is more valuable than either one of those experiments.

The aliphatic region of a 1H-13C HSQC-DEPT is spectrum below. Two coincidental carbon signals are overlapping at 38.51 ppm, one pertaining to a CH while the other a CH2 group. The DEPT-135, attached to the F1 domain, exhibits a weak 13C signal that can easily be misconstrued, for example as an impurity, if not for the extra information from the 2D NMR experiment.

Signals can simply disappear on a DEPT-135 experiment

There are many advantages in working with a 1H-13C HSQC-DEPT spectrum over a 13C DEPT-135 and a 1H-13C HSQC (see Post 1 & Post 2). In most cases, a 1H-13C HSQC-DEPT is more valuable than either one of those experiments.

The aliphatic region of a 1H-13C HSQC-DEPT is spectrum below. Two coincidental carbon signals are overlapping at 38.51 ppm, one pertaining to a CH while the other a CH2 group. The DEPT-135, attached to the F1 domain, exhibits a weak 13C signal that can easily be misconstrued, for example as an impurity, if not for the extra information from the 2D NMR experiment.

When an NMR Instrument Fails

Instruments can fail mechanically and when they do fail, it is important to recognize the signs. For NMR data, any irregularities in the baseline can indicate an instrument issue. The best strategy to minimize instrument failures is to perform regular maintenance and collect data for standards with well documented results prior to any data collection.

The legs used to support the NMR magnet are cushioned by lifts to reduce excessive floor vibrations. If one of the lifts is not performing as it should, then the acquired data will exhibit some vibrational noise. The noise can affect the analysis of the data.

Below are two 1H NMR spectra for the same sample magnified by a factor of ten. The spiky baseline (somewhat symmetrical too) in the top spectrum is a result of a malfunctioning lift on one of the legs. The bottom spectrum does not exhibit these spikes; it was collected from the same NMR instrument with the same sample under identical conditions but the lift was repaired.

For the case where all the legs’ lifts are disabled, Glenn Facey’s blog shows the resulting spectrum.

I would like to give a special thanks to Kent for proposing the idea.

When an NMR Instrument Fails

Instruments can fail mechanically and when they do fail, it is important to recognize the signs. For NMR data, any irregularities in the baseline can indicate an instrument issue. The best strategy to minimize instrument failures is to perform regular maintenance and collect data for standards with well documented results prior to any data collection.

The legs used to support the NMR magnet are cushioned by lifts to reduce excessive floor vibrations. If one of the lifts is not performing as it should, then the acquired data will exhibit some vibrational noise. The noise can affect the analysis of the data.

Below are two 1H NMR spectra for the same sample magnified by a factor of ten. The spiky baseline (somewhat symmetrical too) in the top spectrum is a result of a malfunctioning lift on one of the legs. The bottom spectrum does not exhibit these spikes; it was collected from the same NMR instrument with the same sample under identical conditions but the lift was repaired.

For the case where all the legs’ lifts are disabled, Glenn Facey’s blog shows the resulting spectrum.

I would like to give a special thanks to Kent for proposing the idea.

Will the correct structure please stand up? … Part 2

Part 1 presented a challenge to determine an experiment to distinguish two very similar products from each other, namely 3-methyl-5-(pyridin-2-yloxy)pyridine and 5'-methyl-2H-1,3'-bipyridin-2-one. The products have identical formula weights and the LC/MS and 1H NMR are too similar to draw any conclusion from.

 

The first step is to determine what is different between the two products and then identify an experiment specifically designed to focus on that difference. The obvious difference between the two products is the position of the oxygen atom—an ester group verse a carbonyl group. An FT-IR experiment, as commented by the reader Felipe A., can be used to sort out the products.

 

Other experiments can include the use of reducing agents, 15N NMR, 1H -13C HMBC, 1D NOE, 1H-1H TOCSY, MS2, etc. Note free water, acids and sample concentration can inhibit the use of some of these experiments.

 

A 13C NMR experiment may appear to be another good choice when trying to identify a carbonyl group. However, the carbonyl is part of a conjugated system and so the 13C chemical shift is expected around 160 ppm, which also happens to be expected for the 13C chemical shift of the O-C=N group on the other product.

Will the correct structure please stand up? … Part 2

Part 1 presented a challenge to determine an experiment to distinguish two very similar products from each other, namely 3-methyl-5-(pyridin-2-yloxy)pyridine and 5'-methyl-2H-1,3'-bipyridin-2-one. The products have identical formula weights and the LC/MS and 1H NMR are too similar to draw any conclusion from.

 

The first step is to determine what is different between the two products and then identify an experiment specifically designed to focus on that difference. The obvious difference between the two products is the position of the oxygen atom—an ester group verse a carbonyl group. An FT-IR experiment, as commented by the reader Felipe A., can be used to sort out the products.

 

Other experiments can include the use of reducing agents, 15N NMR, 1H -13C HMBC, 1D NOE, 1H-1H TOCSY, MS2, etc. Note free water, acids and sample concentration can inhibit the use of some of these experiments.

 

A 13C NMR experiment may appear to be another good choice when trying to identify a carbonyl group. However, the carbonyl is part of a conjugated system and so the 13C chemical shift is expected around 160 ppm, which also happens to be expected for the 13C chemical shift of the O-C=N group on the other product.