Will the correct structure please stand up? … Part 2

Part 1 presented a challenge to determine an experiment to distinguish two very similar products from each other, namely 3-methyl-5-(pyridin-2-yloxy)pyridine and 5'-methyl-2H-1,3'-bipyridin-2-one. The products have identical formula weights and the LC/MS and 1H NMR are too similar to draw any conclusion from.

 

The first step is to determine what is different between the two products and then identify an experiment specifically designed to focus on that difference. The obvious difference between the two products is the position of the oxygen atom—an ester group verse a carbonyl group. An FT-IR experiment, as commented by the reader Felipe A., can be used to sort out the products.

 

Other experiments can include the use of reducing agents, 15N NMR, 1H -13C HMBC, 1D NOE, 1H-1H TOCSY, MS2, etc. Note free water, acids and sample concentration can inhibit the use of some of these experiments.

 

A 13C NMR experiment may appear to be another good choice when trying to identify a carbonyl group. However, the carbonyl is part of a conjugated system and so the 13C chemical shift is expected around 160 ppm, which also happens to be expected for the 13C chemical shift of the O-C=N group on the other product.

Will the correct structure please stand up? … Part 2

Part 1 presented a challenge to determine an experiment to distinguish two very similar products from each other, namely 3-methyl-5-(pyridin-2-yloxy)pyridine and 5'-methyl-2H-1,3'-bipyridin-2-one. The products have identical formula weights and the LC/MS and 1H NMR are too similar to draw any conclusion from.

 

The first step is to determine what is different between the two products and then identify an experiment specifically designed to focus on that difference. The obvious difference between the two products is the position of the oxygen atom—an ester group verse a carbonyl group. An FT-IR experiment, as commented by the reader Felipe A., can be used to sort out the products.

 

Other experiments can include the use of reducing agents, 15N NMR, 1H -13C HMBC, 1D NOE, 1H-1H TOCSY, MS2, etc. Note free water, acids and sample concentration can inhibit the use of some of these experiments.

 

A 13C NMR experiment may appear to be another good choice when trying to identify a carbonyl group. However, the carbonyl is part of a conjugated system and so the 13C chemical shift is expected around 160 ppm, which also happens to be expected for the 13C chemical shift of the O-C=N group on the other product.

Will the correct structure please stand up? … Part 1

Many organic chemists—if not all—check to see if a synthetic reaction is complete via TLC and LC/MS and/or 1H NMR. At the same time, the chemists are using the analytical data to verify that the final product is what they intended on making. In some cases, LC/MS and 1H NMR do not adequately distinguish one potential product from another. It then becomes a question of identifying a technique(s) that can clearly verify the correct product.

The chemical structures shown below (3-methyl-5-(pyridin-2-yloxy)pyridine and 5'-methyl-2H-1,3'-bipyridin-2-one) are two possible products for a synthetic reaction. They have an identical formula weight (FW) and a nearly identical MS and 1H NMR (not shown). What other experiments can a chemist/spectroscopist propose that will assist in identifying the correct structure and thus distinguish the ester from the carbonyl product?

 

I would like to give a special thanks to David C. Adams for proposing the idea.

Will the correct structure please stand up? … Part 1

Many organic chemists—if not all—check to see if a synthetic reaction is complete via TLC and LC/MS and/or 1H NMR. At the same time, the chemists are using the analytical data to verify that the final product is what they intended on making. In some cases, LC/MS and 1H NMR do not adequately distinguish one potential product from another. It then becomes a question of identifying a technique(s) that can clearly verify the correct product.

The chemical structures shown below (3-methyl-5-(pyridin-2-yloxy)pyridine and 5'-methyl-2H-1,3'-bipyridin-2-one) are two possible products for a synthetic reaction. They have an identical formula weight (FW) and a nearly identical MS and 1H NMR (not shown). What other experiments can a chemist/spectroscopist propose that will assist in identifying the correct structure and thus distinguish the ester from the carbonyl product?

 

I would like to give a special thanks to David C. Adams for proposing the idea.

My Column is Bleeding

Whenever a GC column is used to identify and/or quantify a sample, the column stationary phase can bleed into the MS source along with the sample. High column bleed can hinder the analysis of a sample. The resulting spectral interference typically manifests itself as discrete peaks and/or an increase in the drift of the baseline, which in turn, produces data with low signal-to-noise and poor sensitivity.  

The GC-EI mass spectra below are two examples showing high column bleed. The ion peaks at m/z 73, 133, 193, 207, 267, 281, 355 and 429 are not part of the purified sample but pertain to the column stationary phase. The major column bleed ion, m/z 207, is a result of the formation of hexamethylcyclotrisiloxane. The presence of these characteristic masses for siloxanes indicates there is a significant column bleed and that the column may need replacing.

  

My Column is Bleeding

Whenever a GC column is used to identify and/or quantify a sample, the column stationary phase can bleed into the MS source along with the sample. High column bleed can hinder the analysis of a sample. The resulting spectral interference typically manifests itself as discrete peaks and/or an increase in the drift of the baseline, which in turn, produces data with low signal-to-noise and poor sensitivity.  

The GC-EI mass spectra below are two examples showing high column bleed. The ion peaks at m/z 73, 133, 193, 207, 267, 281, 355 and 429 are not part of the purified sample but pertain to the column stationary phase. The major column bleed ion, m/z 207, is a result of the formation of hexamethylcyclotrisiloxane. The presence of these characteristic masses for siloxanes indicates there is a significant column bleed and that the column may need replacing.

  

Qualitative Elucidation via TLC Staining

TLC (Thin Layer Chromatography) offers a simple approach to identifying a solvent(s) for separating out a mixture, monitoring a reaction to completion, etc. Furthermore, the TLC plates can be stained to identify the presence or absence of various functional groups such as amines, ketones, etc. This qualitative experiment does offer various drawbacks.

The process of staining typically requires the items shown in the illustration below.

 The following websites offer more insight into the process of staining.

http://webpub.allegheny.edu/employee/s/smurphre/research/visualization.pdf

Org Prep Daily: http://orgprepdaily.wordpress.com/2006/09/27/tlc-staining-solutions/

Curly Arrow Blog: http://curlyarrow.blogspot.com/2006/11/lets-talk-about-tlcs-part-1-vanillin.html

Qualitative Elucidation via TLC Staining

TLC (Thin Layer Chromatography) offers a simple approach to identifying a solvent(s) for separating out a mixture, monitoring a reaction to completion, etc. Furthermore, the TLC plates can be stained to identify the presence or absence of various functional groups such as amines, ketones, etc. This qualitative experiment does offer various drawbacks.

The process of staining typically requires the items shown in the illustration below.

 The following websites offer more insight into the process of staining.

http://webpub.allegheny.edu/employee/s/smurphre/research/visualization.pdf

Org Prep Daily: http://orgprepdaily.wordpress.com/2006/09/27/tlc-staining-solutions/

Curly Arrow Blog: http://curlyarrow.blogspot.com/2006/11/lets-talk-about-tlcs-part-1-vanillin.html

Evaluating a Peak’s Line Shape on a Chromatogram

The line shape of a peak on a chromatogram can offer some insight into the presence of a functional group. However, issues with the instrument are also known to affect the line shape for a peak.

The GC/MS EI+ Total Ion Chromatogram/Current (TIC) below shows five peaks. All of the peaks with the exception of the peak at 1.8 minutes exhibit a symmetrical line shape. The asymmetry of the peak at 1.8 minutes is typical for a structure containing an acidic group (i.e. -COOH).

The peak at 1.8 minutes is 2-ethylhexanoic acid.

Evaluating a Peak’s Line Shape on a Chromatogram

The line shape of a peak on a chromatogram can offer some insight into the presence of a functional group. However, issues with the instrument are also known to affect the line shape for a peak.

The GC/MS EI+ Total Ion Chromatogram/Current (TIC) below shows five peaks. All of the peaks with the exception of the peak at 1.8 minutes exhibit a symmetrical line shape. The asymmetry of the peak at 1.8 minutes is typical for a structure containing an acidic group (i.e. -COOH).

The peak at 1.8 minutes is 2-ethylhexanoic acid.

Verifying, Confirming, Making Sure … Part 2

In the constant pursuit of new pharmaceutical drugs, process chemists (sometimes referred to as medicinal or synthetic chemists) must investigate all impurities detected in a new drug manufacturing process. The chemist’s procedure is simple: identify, elucidate and synthesize each and every single impurity.

The chromatogram (UV detector set at 254 nm) below shows three peaks. The large peak at 5.51 min. is the active pharmaceutical ingredient (API). The two small peaks on either side of the API are impurities from the manufacturing process. Depending on the dose and potency of the drug substance, typical regulatory requirements for impurities mandate that any peak with a threshold greater than 0.1% be identified, elucidated and synthesized.

Verifying, Confirming, Making Sure … Part 2

In the constant pursuit of new pharmaceutical drugs, process chemists (sometimes referred to as medicinal or synthetic chemists) must investigate all impurities detected in a new drug manufacturing process. The chemist’s procedure is simple: identify, elucidate and synthesize each and every single impurity.

The chromatogram (UV detector set at 254 nm) below shows three peaks. The large peak at 5.51 min. is the active pharmaceutical ingredient (API). The two small peaks on either side of the API are impurities from the manufacturing process. Depending on the dose and potency of the drug substance, typical regulatory requirements for impurities mandate that any peak with a threshold greater than 0.1% be identified, elucidated and synthesized.